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- 3 min readTo ignore a character followed by random numbers using regex, you can use the following pattern: \w\d+ This pattern will match an alphanumeric character followed by one or more digits. You can use this pattern in your regular expression to ignore such characters with random numbers.[rating:f57ed76a-ab98-4054-8d2c-1baca0521009]What is the best approach for handling cases where characters may or may not have random numbers in regex.
- 3 min readTo separate two groups with a regex, you can use parentheses to create capturing groups. By enclosing the patterns for each group within parentheses, you can later refer to each group separately in your code. For example, if you have a text that contains both numbers and words, you can use a regex pattern like "(\d+)(\D+)" to separate the numbers and words into two groups.
- 7 min readTo limit a list of strings using a regular expression pattern, you can loop through each string in the list and check if it matches the desired pattern using regex functions in your programming language of choice. If a string does not match the pattern, you can remove it from the list. This approach allows you to filter out strings that do not meet the specified criteria based on the regex pattern.
- 2 min readTo split by newline and ignore blank lines using regex, you can use the following pattern: /\S+/g. This regex pattern matches one or more non-whitespace characters, effectively splitting the input string by newline characters and ignoring blank lines.
- 3 min readTo replace part of a URL using regex, you first need to construct a regular expression pattern that matches the specific portion of the URL you want to replace. This pattern should include any necessary escaping of special characters within the URL.Once you have created the regex pattern, you can use a method such as String.prototype.replace() in JavaScript to replace the matched portion of the URL with the desired new value.
- 6 min readTo get "m" meters and "km" from a string using regex, you can use the following pattern:for meters: \b(\d+)\s*m\bfor kilometers: \b(\d+)\s*km\bExplanation:\b asserts a word boundary(\d+) captures one or more digits\s* matches zero or more whitespace charactersm and km are the literal characters for meters and kilometers respectivelyYou can use these regex patterns in your programming language of choice to extract the desired values from a given input string.
- 4 min readTo match all words after a specific expression with regex, you can use a positive lookbehind assertion to match the expression, followed by a pattern that captures the words you want to match.For example, if you want to match all words after the expression "hello", you can use the following regex pattern: (?<=hello\s)\w+ In this pattern:(.
- 4 min readTo split a string into parts using regex, you can use the split() method provided by most programming languages. This method takes a regular expression as its argument and splits the string based on the matching pattern.
- 6 min readTo find a sentence and a 13 digit code in a paragraph using regex, you can use pattern matching techniques. To find a sentence, you can use a regex pattern that matches a complete sentence, such as '[A-Z][^.?!]*[.?!]'. To find a 13 digit code, you can use a pattern that matches exactly 13 digits, such as '\d{13}'. You can combine these patterns in your regex search to find both the sentence and the 13 digit code in a paragraph.
- 3 min readIn regex, conditions can be written using groups and backreferences. You can use parentheses to create a group of characters and then refer back to that group using a backreference. For example, if you want to match a word that is repeated twice, you can use a backreference like \b(\w+)\b\s+\1\b to match the same word repeated twice. Additionally, you can use OR statements (|) to create conditions where either option can be matched.
- 4 min readTo limit the decimal point in a regex, you can specify the maximum number of decimal places allowed. For example, if you want to limit a number to two decimal places, you can use the following regex pattern:^[0-9]+(.[0-9]{1,2})?$In this pattern, the {1,2} specifies that there can be one or two decimal places. You can adjust this number to limit the decimal places as needed.