You can find full duplicate rows in Oracle by using the following SQL query:
SELECT * FROM your_table WHERE ROWID NOT IN (SELECT MIN(ROWID) FROM your_table GROUP BY column1, column2, ...);
This query will return all rows that have duplicate values across all columns in the specified table. The ROWID function is used to identify which rows are duplicates, and the MIN function is used to find the minimum ROWID for each group of duplicate rows.
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What is the best practice for identifying full duplicates in Oracle table?
One common practice for identifying full duplicates in an Oracle table is to use a combination of the GROUP BY clause and the HAVING clause in a SQL query.
Here is an example query that can be used to identify full duplicates in an Oracle table based on specific columns:
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SELECT column1, column2, COUNT(*) FROM your_table GROUP BY column1, column2 HAVING COUNT(*) > 1; |
In this query, replace column1 and column2 with the column names in your table that you want to check for duplicates. The COUNT(*) function is used to count the number of occurrences of each combination of values in the specified columns. The GROUP BY clause groups the rows based on the specified columns, and the HAVING clause filters out the groups that have more than one occurrence.
By running this query, you will be able to identify the full duplicates in your Oracle table based on the specified columns.
What is the easiest method to locate full duplicates in Oracle database?
The easiest method to locate full duplicates in an Oracle database is by using the SQL query below:
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SELECT * FROM table_name GROUP BY column1, column2, ... HAVING COUNT(*) > 1; |
Replace table_name with the name of the table you want to check for duplicates and column1, column2, ... with the columns you want to check for duplicates in. This query will group the records by the specified columns and then return only the records that have a count greater than 1, indicating that they are duplicates.
How to detect and list complete duplicate rows in Oracle database?
To detect and list complete duplicate rows in an Oracle database, you can use the following SQL query:
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SELECT * FROM ( SELECT *, COUNT(*) OVER (PARTITION BY <column_name1>, <column_name2>, ...) AS duplicate_count FROM <table_name> ) WHERE duplicate_count > 1; |
Replace <column_name1>, <column_name2>, ... with the column names that you want to use for detecting duplicates, and <table_name> with the name of the table you are querying from.
This query will return all rows that have duplicates based on the specified columns. The PARTITION BY clause in the COUNT() function will group the rows based on the specified columns, and then the duplicate_count column will show the count of duplicates for each group. Finally, the outer query filters only the rows with a duplicate count greater than 1, effectively listing only the complete duplicate rows.
