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How to Get Only Url Results In Sparql Query?

5 minutes read

To get only URL results in a SPARQL query, you can use the FILTER function to filter out non-URL results. You can specify that the result should be of type URI by using the datatype http://www.w3.org/2001/XMLSchema#anyURI. This will only return results that are valid URLs. Additionally, you can use regular expressions to further refine the results and ensure that only URLs are returned. By combining these techniques, you can effectively filter out non-URL results in a SPARQL query.

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How to refine my SPARQL query to return only URLs?

To refine your SPARQL query to return only URLs, you can use the FILTER clause with the REGEX function to filter out results that do not match a URL pattern.


Here is an example of how you can modify your query:

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SELECT ?url
WHERE {
  ?s ?p ?url .
  FILTER(REGEX(?url, "^http://|^https://"))
}


In this query, we are selecting only the ?url variable, and using the FILTER clause with the REGEX function to match only URLs that start with "http://" or "https://". This will exclude any results that do not match this URL pattern.


What is the syntax for filtering URL results in SPARQL?

To filter URL results in SPARQL, you can use the FILTER clause along with the regex function. Here is the syntax for filtering URL results in SPARQL:

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SELECT ?url
WHERE {
  ?s ?p ?url .
  FILTER regex(str(?url), "example.com")
}


In this example, we are filtering results where the URL contains "example.com". You can replace "example.com" with any other URL pattern you want to filter.


What is the technique for narrowing down SPARQL results to include only URLs?

One technique for narrowing down SPARQL results to include only URLs is to use the FILTER clause with a regular expression pattern that matches URLs.


For example, you can use the following SPARQL query to retrieve all resources that have a URL property:

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SELECT ?resource WHERE {
  ?resource ?property ?value .
  FILTER(regex(str(?value), "^(http|https)://.*"))
}


In this query, the FILTER clause uses the regex function to filter out only those values that start with "http://" or "https://", which are common patterns for URLs.


This will return only resources that have a URL property, excluding other types of values such as literals or blank nodes.


How to refine my SPARQL query to show only web addresses?

To refine your SPARQL query to show only web addresses, you can specify a filter condition that checks if the value is a valid URL format. Here is an example of how you can modify your SPARQL query:

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SELECT ?webAddress
WHERE {
  ?s <http://xmlns.com/foaf/0.1/homepage> ?webAddress .
  FILTER(STRSTARTS(str(?webAddress), "http://") || STRSTARTS(str(?webAddress), "https://"))
}


In this query, we are selecting all web page addresses (?webAddress) where the value for the predicate <http://xmlns.com/foaf/0.1/homepage> starts with "http://" or "https://", which indicates that it is a web address. By using the FILTER condition, we are filtering out any values that do not meet this criteria.


What keyword can I use to target URLs in a SPARQL query?

The keyword "FILTER" can be used to target URLs in a SPARQL query.

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