Best TypeScript Development Resources to Buy in October 2025
Programming TypeScript: Making Your JavaScript Applications Scale
Effective TypeScript: 83 Specific Ways to Improve Your TypeScript
TypeScript Cookbook: Real World Type-Level Programming
Learning TypeScript: Enhance Your Web Development Skills Using Type-Safe JavaScript
Learn React with TypeScript: A beginner's guide to building real-world, production-ready web apps with React 19 and TypeScript
Essential TypeScript 5, Third Edition
Mastering TypeScript: Build enterprise-ready, modular web applications using TypeScript 4 and modern frameworks, 4th Edition
React and React Native: Build cross-platform JavaScript and TypeScript apps for the web, desktop, and mobile
Full-Stack Web Development with TypeScript 5: Craft modern full-stack projects with Bun, PostgreSQL, Svelte, TypeScript, and OpenAI
In TypeScript, the equivalent of a Rust struct is an interface. Interfaces in TypeScript can be used to define the shape of an object, including its properties and methods. These interfaces can then be implemented by classes or objects to ensure that they adhere to a specific structure. The key difference is that TypeScript interfaces are used for defining the shape of objects, whereas Rust structs are used for defining the structure of data types.
What is the TypeScript equivalent of Rust's dereferencing operator for structs?
In TypeScript, you can use the ! operator to perform null assertion and access the properties of a struct. This is similar to Rust's dereferencing operator.
For example, if you have a struct User with a property name, you can dereference and access the name property like this:
interface User { name: string; }
const user: User | null = getUser();
const userName = user!.name;
In this example, user! asserts that user is not null before accessing its name property. This is equivalent to Rust's dereferencing operator.
How to enforce type safety in TypeScript structs like in Rust?
In TypeScript, you can enforce type safety in structs by using interfaces. Here is an example of how you can create a struct-like interface with type safety:
interface User { id: number; name: string; age: number; }
const user: User = { id: 1, name: "John", age: 30 };
// This will throw an error because 'age' must be a number const invalidUser: User = { id: 2, name: "Jane", age: "30" };
By defining an interface with specific properties and types, you can ensure that any object that conforms to that interface will have the correct structure and data types. This is similar to how structs work in Rust, where you define a struct with specific fields and data types to enforce type safety.
What is the TypeScript equivalent of Rust's associated functions in structs?
In TypeScript, there is no direct equivalent of Rust's associated functions in structs. However, one way to achieve similar functionality is to use static methods in TypeScript classes.
Here is an example in TypeScript:
class MyClass { static myAssociatedFunction() { console.log('Hello from associated function'); } }
MyClass.myAssociatedFunction(); // Output: Hello from associated function
In this example, myAssociatedFunction is defined as a static method on the MyClass class, similar to an associated function in Rust. You can call the static method directly on the class without needing an instance of the class.