To check if three numbers are different in Kotlin, you can compare them using conditional statements. You can use nested if-else statements to compare each pair of numbers and ensure that all three numbers are different from each other. You can also use the `distinct`

function to remove duplicate elements from a list or array containing the three numbers, and then check if the size of the resulting list is equal to 3. This would indicate that all three numbers are different.

## How to check if three numbers are different in Kotlin?

One way to check if three numbers are different in Kotlin is to use an if statement to compare all three numbers. Here's an example code snippet to demonstrate this:

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fun main() { val num1 = 5 val num2 = 10 val num3 = 15 if (num1 != num2 && num1 != num3 && num2 != num3) { println("The three numbers are different") } else { println("The three numbers are not all different") } } |

In the above code, we are checking if `num1`

, `num2`

, and `num3`

are all different by comparing each number with the other two using the `!=`

operator. If all three numbers are different, the program will print "The three numbers are different". Otherwise, it will print "The three numbers are not all different".

## How can I detect identical numbers within three values in Kotlin?

One way to detect identical numbers within three values in Kotlin is to compare each value against the others using the `==`

operator. Here is an example code snippet to demonstrate this:

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fun detectIdenticalNumbers(num1: Int, num2: Int, num3: Int): Boolean { return num1 == num2 || num1 == num3 || num2 == num3 } fun main() { val num1 = 5 val num2 = 10 val num3 = 5 if (detectIdenticalNumbers(num1, num2, num3)) { println("There are identical numbers within the three values.") } else { println("There are no identical numbers within the three values.") } } |

In this code snippet, the `detectIdenticalNumbers`

function takes three integer arguments and checks if any two of them are identical by comparing each pair of values. The `main`

function demonstrates how to call and use this function with sample values.

## How to ensure that three values are all unique in Kotlin?

One way to ensure that three values are all unique in Kotlin is to use a Set data structure. A Set is a collection that does not allow duplicate elements, so if you add all three values to a Set and the size of the Set is equal to 3, then you can be sure that all three values are unique.

Here is an example of how you can use a Set to ensure uniqueness of three values in Kotlin:

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val value1 = 10 val value2 = 20 val value3 = 30 val uniqueValues = setOf(value1, value2, value3) if (uniqueValues.size == 3) { println("All three values are unique") } else { println("Not all three values are unique") } |

In this example, we create three values `value1`

, `value2`

, and `value3`

, and add them to a Set called `uniqueValues`

. We then check if the size of `uniqueValues`

is equal to 3, which means that all three values are unique. If the size is not equal to 3, then not all three values are unique.

## What is the standard procedure for confirming three distinct numbers in Kotlin?

One standard procedure for confirming three distinct numbers in Kotlin is to use conditionals and comparisons. Here is an example code snippet that demonstrates this procedure:

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fun main() { println("Enter three numbers:") val num1 = readLine()!!.toInt() val num2 = readLine()!!.toInt() val num3 = readLine()!!.toInt() if(num1 != num2 && num1 != num3 && num2 != num3) { println("The numbers $num1, $num2, and $num3 are distinct.") } else { println("The numbers are not distinct.") } } |

In this code snippet, the user is prompted to enter three numbers which are then stored in variables `num1`

, `num2`

, and `num3`

. A series of conditional statements are used to compare these numbers and determine if they are distinct. If all three numbers are distinct, a message confirming this is printed, otherwise a message indicating that the numbers are not distinct is printed.